When falling freely, a body undergoes the gravity acceleration (a=9.8) in m*s-2, that increases the body's speed proportionally to the fall duration (dT) in s. Hence (1): dS=a*dT where dS is the increase of speed in m/s.
But the speed is also defined as the distance dH (in our case the height of fall) divided by the time slot (dT) it took the body to fall from dH. Hence (2): dS=dH/dT
Of course, expression (1) = expression (2), hence we get (3): dS=dH/dT = a*dT
By integrating the expression (3) on the actual time T it takes to fall from the total height H, we obtain (4): T*T=2H/a
wich is equivalent to say: (5): T=square root(2H/a)
where T is the time of fall in seconds, from an height H in metres.
Replacing T by its expression (5) in the expression (1) gives the speed of impact
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(6): S = square root (2aH) = square root (19.6*H)
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The speed of impact on landing S, is in metres per second and H, the height of the wall is in metres. On Earth a=9.8m*s-2
To get the resulting speed in kilometres per hour, multiply by 3.6
To get the resulting speed in miles per hour, multiply by 2.237
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As an example, a drop off from an height of 3 metres (about 10 feet), gives a landing vertical speed of 7.6 metres per second.
In kilometres per second, that gives 7.6*3.6= 27.4 kilometres/hour. In miles per second, that gives 7.67*2.237= 17 miles/hour.
You wouldn't ride into a wall for fun at that speed!
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